Unit III Lesson 4

Annihilator Approach to
Method of Undetermined Coefficients

Annihilator operators, what they are what they do, the basic types.
Proof by induction of one of the annihilator types.
Find some annihilator operators for functions of various types.
Outline of the technique for solving non-homogeneous equations using annihilator method.
Example using the annihilator method for a non-homogeneous equation.


Note that any nth order linear DE can be written with the differential operator D:

.

More simply, we could write L(y)=g(x) for where L is a linear operator.

Recall also that operators can be factored.

Example:

(D2-5D+6)y=(D-3)(D-2)y


Def: Annihilator Operator
If L is a linear differential operator with constant coefficients and f is a sufficiently differentiable function such that L(f(x))=0, then L is an annihilator of f

Examples of annihilators:
  1. Dn annihilates 1,x,x2,…xn-1.
  2. Dn also annihilates c1+c2x+c3x2+…+cn-1xn-1
  3. (D-A)n annihilates eAx, xeAx, x2eAx, …, xn-1eAx
  4. (D-A)n annihilates C1eAx+C2xeAx+C3x2eAx+ …+ Cn-1xn-1eAx
  5. (D2-2AD+(A2+B2))n annihilates all of these:
    eAxcos(Bx), eAxsin(Bx), xeAxcos(Bx), xeAxsin(Bx), x2eAxcos(Bx), x2eAxsin(Bx),…,xn-1eAxcos(Bx), xn-1eAxsin(Bx)  


Ex1. Show that (D-A)n annihilates xn-1eAx by induction.

Take this link after you've tried it yourself.


Here are some proof jokes if you are interested:

Methods of proof

Weird humor link.


Ex2. Find an annihilator for each function:
  1. f(x)=x4-7x2+2
  2. f(x)=e2x
  3. f(x)=4e2x-xe2x+x2e2x
  4. (harder) f(x)=9xe2xcos(3x)-5xe2xsin(3x) (hint: look at 5 above)
  5. f(x)=Acos(kx)+Bsin(kx)

Take this link after you’ve tried these.


Technique for using annihilator method:
  1. Find yc, the solution of the homogeneous equation L(y)=0
  2. Operate on both sides of the non-homogeneous equation L(y)=g(x) with an annihilator L1 that annihilates g(x).
  3. Find the general solution of the higher order differential equation L1(L(y))=0.
  4. Delete from the solution of the equation all duplicates in yc, and form a linear combination yp of the terms that remain. This is the ‘form’ of the particular solution to L(y)=g(x). We need the actual coefficients, so
  5. Substitute this yp and its derivatives in the original equation and solve for the coefficients, thus finding yp.
  6. The solution is y=yc+yp 


Ex3. (Hard!) Solve the differential equation: y’’’+4y’=excos(2x)

Take this link after you've suffered for a while yourself.

Comment: I don’t think any of the assigned problems are this tough!


Ex4. Annihilator problem.
****assignment****
Chapter 4 Section 5
Problems 1,7,13,15,17,21,23 (you don’t have to solve any of these!)
35,49,53 (you do have to solve these), 69(IVP)